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result(s) for
"Berezin symbol"
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A new mean-Berezin norm for operators in reproducing kernel Hilbert spaces
2025
A functional Hilbert space is defined as the Hilbert space
K
of complex-valued functions defined on a set Θ. In this space, the evaluation functionals
ψ
ε
(
h
)
=
h
(
ε
)
, for
ε
∈
Θ
, are continuous on
K
. In this paper, we introduce the mean-Berezin norm
∥
⋅
∥
ρ
t
, defined as follows:
∥
G
∥
M
ρ
t
=
sup
κ
,
ξ
∈
Θ
{
(
|
〈
G
k
ˆ
κ
,
k
ˆ
ξ
〉
|
)
ρ
t
(
|
〈
G
∗
k
ˆ
κ
,
k
ˆ
ξ
〉
|
)
}
,
for
0
⩽
t
⩽
1
,
where
G
∈
O
(
K
)
and
ρ
t
represents an interpolation path of a symmetric mean
ρ
. Using the definition of the mean-Berezin norm, we explore some related new inequalities For instance, if
G
∈
O
(
K
)
, then
1
2
∥
|
G
|
2
r
+
|
G
∗
|
2
(
1
−
r
)
∥
ber
⩾
∥
G
∥
M
ρ
,
where
0
⩽
r
⩽
1
and
ρ
is a mean such that
ρ
⩽
∇
.
Journal Article
An extension of the Euclidean Berezin number
2023
The Berezin transform à of an operator A, acting on the reproducing kernel Hilbert space ℍ = ℍ(Θ) over some (non-empty) set Θ, is defined by Ã(λ) = ⟨Ak̂λ,k̂λ
⟩ (λ ∈ Θ), where
k
^
λ
=
k
λ
‖
k
λ
‖
is the normalized reproducing kernel of ℍ. The Berezin number of an operator A is defined by
ber
(
A
)
=
sup
λ
∈
Θ
|
A
˜
(
λ
)
|
=
sup
λ
∈
Θ
|
〈
A
k
^
λ
,
k
^
λ
〉
|
. In this paper, by using the definition of g-generalized Euclidean Berezin number, we obtain some possible relations and inequalities. It is shown, among other inequalities, that if Ai
∈ 𝕃(ℍ(Θ)) (i = 1,..., n), then
ber
g
(
A
1
,
…
,
A
n
)
≤
g
−
1
(
∑
i
=
1
n
g
(
ber
(
A
i
)
)
)
≤
∑
i
=
1
n
ber
(
A
i
)
in which g : [0, ∞) → [0, ∞) is a continuous increasing convex function such that g(0) = 0.
Journal Article
The weighted Davis-Wielandt Berezin number for reproducing kernel Hilbert space operators
by
Eslami Mahdiabadi, Nooshin
,
Petrushka, Mykola
,
Hajmohamadi, Monire
in
Analysis
,
Applications of Mathematics
,
Berezin set
2025
A functional Hilbert space is the Hilbert space of complex-valued functions on some set
Θ
⊆
C
that the evaluation functionals
φ
λ
(
f
)
=
f
(
λ
)
,
λ
∈
Θ
are continuous on
H
. Then, by the Riesz representation theorem, there is a unique element
k
λ
∈
H
such that
f
(
λ
)
=
〈
f
,
k
λ
〉
for all
f
∈
H
and every
λ
∈
Θ
. The function
k
on
Θ
×
Θ
defined by
k
(
z
,
λ
)
=
k
λ
(
z
)
is called the reproducing kernel of
H
. In this study, we defined the weighted Davis-Wielandt Berezin number, and then we obtained some related inequalities. It is shown, among other inequalities, that if
X
∈
L
(
H
)
and
ν
∈
[
0
,
1
]
, then
1
2
(
ber
2
(
X
ν
+
|
X
ν
|
2
)
+
c
ber
2
(
X
ν
−
|
X
ν
|
2
)
)
≤
d
w
ber
ν
2
(
X
)
≤
1
2
(
ber
2
(
X
ν
+
|
X
ν
|
2
)
+
ber
2
(
X
ν
−
|
X
ν
|
2
)
)
,
where
X
ν
=
(
1
−
2
ν
)
X
∗
+
X
. Some bounds for the weighted Davis-Wielandt Berezin number are also established.
Journal Article
Development of the Berezin Number Inequalities
2023
We present new bounds for the Berezin number inequalities which improve on the existing bounds. We also obtain bounds for the Berezin norm of operators as well as the sum of two operators.
Journal Article
Bounds for the Berezin number of reproducing kernel Hilbert space operators
2023
In this paper, we find new upper bounds for the Berezin number of the product of bounded linear operators defined on reproducing kernel Hilbert spaces. We also obtain some interesting upper bounds concerning one operator, the upper bounds obtained here refine the existing ones. Further, we develop new lower bounds for the Berezin number concerning one operator by using their Cartesian decomposition. In particular, we prove that
ber
(
A
)
≥
1
2
ber
(
ℜ
(
A
)
±
J
(
A
)
)
, where ber(A) is the Berezin number of the bounded linear operator A.
Journal Article
Inequalities of Generalized Euclidean Berezin Number
In this paper, we present several Berezin number inequalities involving extensions of Euclidean Berezin number for n operators. Among other inequalities for (T₁, . . . , Tn
) ∈ 𝔹(𝓗) we show that
ber
p
p
(
T
1
,
…
,
T
n
)
≤
1
2
p
ber
(
∑
i
=
1
n
(
|
T
i
|
+
|
T
i
*
|
)
p
)
, where p > 1.
Journal Article
Refined Berezin number inequalities via superquadratic and convex functions
2023
In this paper, we generalize and refine some Berezin number inequalities for Hilbert space operators. Namely, we refine the Hermite-Hadamard inequality and some other recent results by using the concept of superquadraticity and convexity. Then we extend these inequalities for the Berezin number. Among other inequalities, it is shown that if S, T ∈ 𝓛(𝓗(Ω)) such that ber(T) ≤ ber(|S|) and f is a non-negative superquadratic function, then f (ber (T)) ≤ ber(f (|S|)) − ℓber ϵ f (∥S| − ber (T)|).
Journal Article
New inequalities for some quadratic forms and related results
2025
We prove some new Jensen type inequalities for the Berezin symbol of self-adjoint operators and some class of positive operators on the reproducing kernel Hilbert space ℋ(Ω) over some set Ω. Recall that the Berezin symbol
A
~
of operator A on ℋ(Ω) is defined by the following special type of quadratic form:
A
~
(
λ
)
:
=
〈
A
k
^
λ
,
k
^
λ
〉
,
λ
∈
Ω
, where 𝑘𝜆 is the reproducing kernel of the space ℋ(Ω), i.e.,
f
(
λ
)
=
〈
f
,
k
^
λ
〉
for all 𝑓 ∈ ℋ(Ω) and
λ
∈
Ω
;
k
^
λ
:
=
k
λ
‖
k
λ
‖
ℋ
(
Ω
)
is the normalized reproducing kernel.
Journal Article
Berezin Number Inequalities via Convex Functions
2022
The Berezin symbol à of an operator A on the reproducing kernel Hilbert space 𝓗(Ω) over some set Ω with the reproducing kernel kξ
is defined by
A
˜
(
ξ
)
=
〈
A
k
ξ
‖
k
ξ
‖
,
k
ξ
‖
k
ξ
‖
〉
,
ξ
∈
Ω
. The Berezin number of an operator A is defined by
ber
(
A
)
:
=
sup
ξ
∈
Ω
|
A
˜
(
ξ
)
|
. We study some problems of operator theory by using this bounded function Ã, including treatments of inner product inequalities via convex functions for the Berezin numbers of some operators. We also establish some inequalities involving of the Berezin inequalities.
Journal Article
New estimations for the Berezin number inequality
2020
In this paper, by the definition of Berezin number, we present some inequalities involving the operator geometric mean. For instance, it is shown that if X,Y,Z∈L(H) such that X and Y are positive operators, then berr((X♯Y)Z)≤ber((Z⋆YZ)rq2q+Xrp2p)−1pinfλ∈Ω([X˜(λ)]rp4−[(Z⋆YZ)˜(λ)]rq4)2, in which X♯Y=X12(X−12YX−12)12X12, p≥q>1 such that r≥2q and 1p+1q=1.
Journal Article